JEE Main Counselling & Seat Allotment 2019: Schedule & Procedure


JEE Main Counselling 2019: Only candidates securing qualifying marks in JEE Main will be eligible to participate in the counselling process. The seat allotment process will take place in June 2019.

JEE Main Counselling will commence after declaration of JEE Main 2019 result and JEE Advanced Result as well. National Testing Agency will use Normalization process and percentile score to rank the candidates for the first time.

Read JEE Main 2019 Normalization Procedure and Tie Breaker Rules

There are 3 counselling processes in JEE Main – JoSAA, CSAB SFTI and CSAB NEUT. Around 100 institutes participate in JEE Main counselling and admission process.

JoSAA Counselling is held for JEE Main and JEE Advanced qualified candidates.

  • CSAB SFTI is the separate counselling procedure held by Central Seat Allocation Board for 17 Self-Financed Technical Institutions.
  • CSAB NEUT is conducted for supernumerary seats in North East and Union Territories.
  • CSAB Counselling will take place after the JoSAA Counselling.

Read on to know more about JEE Main Counselling 2019. 

Event Date (tentative)
Declaration of JEE Advanced 2019 AIR by JAB 2nd week of June 2019
Availability of Class 12th marks by CBSE to JoSAA 3rd week of June 2019
Declaration of JEE Main 2019 AIRs by Joint Apex Board Last week of June 2019
Filling of Choices of academic programs in participating Institutes Last week of June 2019
Process of Reconciliation of the data ion of seats and document verification begins from Last week of June 2019
(First round)Seat allocation Last week of June 2019
(First round)Acceptance of seat 1st week of July 2019
Display of seats filled/availability status 1st week of July 2019
(Second round)Seat allocation 1st week of July 2019
(Second round)Acceptance/withdrawal of seat 1st week of July 2019
Display of seat status of filled/available seats After 2nd round seat acceptance
(Third round) Seat allocation After 2nd round seat acceptance
(Third round) Acceptance/withdrawal of seat 2-3 days after seat allotment of 3rd round
Display of seats status of filled/available seats After 3rd round seat acceptance
(Fourth round) Seat allocation After 3rd round seat acceptance
(Fourth round)Acceptance of seats 1-2 days of seat allocation of 4th round
Beginning of academic sessions 4th week of July 2019
Reporting of candidates in the campus of admitting institutes (NITs); Schedule for IITs 4th week of July 2019
Beginning of Academic session for preparatory courses at IITs 4th week of July 2019
Beginning of Academic sessions at NITs 4th week of July 2019

JEE Main Counselling 2019

Check here in the important JEE Main Counselling Dates

JEE Main Seat Allocation Process

  • The Seat Allotment Process is purely based on the merit and the choices made by candidates in JoSAA and CSAB.
  • Once the allotted seat is rejected, candidates will not be allowed to participate in the further rounds of the counselling.
  • After the JoSAA seat allotment, CSAB counselling will take place.

JEE Main 2019 Seat Matrix

Institutes Total Number of Seats
Indian Institute of Information Technology (IIITs) 4023
National Institute of Technology (NITs) 17967
Government Funded Technical Institutes 4683

JEE Main counselling involves following steps:

  1. Online Registration:Register online by providing JEE Main Roll Number and Password.
  2. Online Choice Filling and Locking:Fill and lock the choices of college and B.Tech course in order of preference. The allotment of seats will be based on the choice preference.
  3. Seat Allotment:Based on merit ranking, availability of seats and choice preference, seats will be allotted to eligible candidates. Before the actual allotment of seats, mock seat allotment will be carried out.
  4. Payment of Fees and Seat Acceptance:Post the seat allotment, candidates will have to choose any one of the following options:
  • Freeze:Candidates who are satisfied with the allotted seat and do not wish to participate in the seat allotment process, may choose this option.
  • Float:Those who want to keep the allotted seat but wish to upgrade their seat, may choose this option.
  • Slide:Those who want to keep the allotted seat in the same institute but wish to upgrade the course.
  • Withdraw:Candidates who have allocated the seat but wish to withdraw the admission, can withdraw the seat by reporting to the institute before the last date of seat allotment.

The fees can be paid through SBI Net Banking/ e-Challan. The seat acceptance fee is INR 45,000 for all the candidates, candidates belonging to SC/ ST/ SC-PwD/ ST-PwD/ GEN-PwD/ OBC-NCL-PwD category will have to pay INR 20,000 as seat acceptance fee.

  1. Document Verification:The documents have to be verified at the help centres. The following list of documents have to be carried for the purpose of verification:
  • 3 passport size photographs (the same as uploaded during registration)
  • Provisional JoSAA seat allotment letter
  • Photo identity card
  • Proof of seat acceptance fee payment
  • JEE Main 2019 Admit Card
  • Date of birth proof
  • JEE Main 2019 Score Card
  • Class XII Mark sheet
  • Category certificate (if applicable)
  1. Final Reporting:After the verification of documents, candidates will have to report to the institute and there they have to pay the balanced fee.

JEE Main 2019 Spot Counselling

  • In case of vacant seats even after the usual rounds of JEE Main counselling, then JoSAA conducts Spot Counselling for the allocation of such seats.
  • It is not required to register separately for the spot counselling round in JEE Main.
  • Any applicant who has not been allotted any seat during the usual rounds of counselling can appear for the spot counselling process.
  • Also, candidates who did not apply earlier for the usual rounds of allotment can appear for Spot Counselling.
  • But, candidates who have missed the registration for JEE Main Counselling earlier have to register for Spot Counselling.
  • Candidates applying fresh for the JEE Main Spot Counselling will have to lock the choices and make the payment of the fee before the last date.


JEE Advanced 2019 admit card to release today: Steps to download


The JEE Advanced 2019 hall tickets are expected to be released today by IIT Roorkee.

The JEE advanced exams will be held on 27 May 2019.

JEE Advanced 2019 admit card: The Indian Institute of Technology (IIT), Roorkee is expected to release the admit card for Joint Entrance Examination (JEE), Advanced for admissions to IITs today i.e. May 20, 2019 at 10 am. The exam will be held on May 27, 2019.

The hall tickets or admits cards will be released on the official

According to the information provided by IIT, Roorkee, which is organising the JEE this year, the admit card will be available till May 27, 2019.

The admit card will be made available in online mode.

Those candidates who qualified the JEE Mains and have registered for JEE advanced on the official website will have to go to the website to download the admit card after 10 am.

A total of 2,24,000 students have qualified JEE Mains and are eligible to give JEE Advanced.

ALSO READ: JEE Main April Paper 2 results 2019 released: Steps to check score
Here are the steps to download JEE Advanced 2019 admit card

Step1:  Visit the official web site

Step 2: Go to the link ”admit card” on the homepage and click on it. You can also use this direct link

Step 3: Use your registration details to log-in

Step 4: Download the admit card and take print outs

Till now, admit card link is not yet active. It is expected to get active only after 10 am on May 20, 2019.

Important details to check on the JEE Advanced 2019 admit card

The admit card will contain details of students. The students are expected to go through it and check if they are correct. The details will include the name of the candidate, roll number, registration number, and address for correspondence, exam centre, exam timings, reporting time and other such details.

The candidates are advised to carry all the relavant documents especially the JEE Advanced 2019 admit card and a valid ID proof.

Here is the link to important dates for JEE Advanced 2019 exams-



Pre-RMO exam: First step to Indian Mathematical Olympiad 2019-20

  1. The National Board for Higher Mathematics (NBHM) is in charge of the mathematical Olympiad activity for the country. Mathematics Teachers’ Association (India) (MTA) has been recognized by NBHM as the body which will conduct PRMO and whose results will be recognized by HBCSE for further selection processes of the Indian Mathematical Olympiad. The pre-Regional Mathematical Olympiad (PRMO) exam will be held on August 11, 2019, between 10.00 AM to 1.00 PMat different centres all over India. In order to be eligible for selection to the next stage of the Mathematical Olympiad Programme in India, namely, the Regional Mathematical Olympiad (RMO) it is mandatory that students qualify through this centrally administered PRMO. No other independently administered examinations will be recognized.
  2. The PRMO exam will be organized by MTA (Mathematics Teachers’ Association). The website for PRMO is available at
  3. Eligibility: Candidates born on or after August 1, 2000 and studying in Class 8, 9, 10, 11 or 12 are eligible to write PRMO 2019. Further, the candidates must be Indian citizens. Provisionally, students with OCI cards are eligible to write the PRMO, subject to conditions as explained below:

As per the orders of the Madras High Court, students with OCI status will not be eligible for selection to the Indian team in the International Mathematical Olympiad. However, such students are provisionally eligible for selection at ALL prior stages, up to and including the IMOTC provided they fulfil all other criteria. This policy is subject to revision without prior notice depending on any further orders issued by the courts, or by a competent Government authority.

  1. It is each student’s responsibility to determine if she/he satisfies the eligibility norms for each stage of the Mathematical Olympiads. If, at any stage, it is found that the student does not meet the eligibility norms, she/he may face immediate disqualification from the programme.
  2. The PRMO will be a machine-correctable 3-hour duration test with 30 questions. Each question has an answer which is a number with one or two digits. Sample PRMO questions and Sample OMR sheet showing marked answers can be downloaded


  1. Schools can register as “registration centres” for PRMO at this link: (registrations will start soon) In order to register students individually or in groups, the registration centres will collect the exam fees from the students from any school and register them at the portal. The fee will be Rs 230.00 for each non-KV and non-JNV student. The registration centre will retain Rs 20.00 (to be used for making student lists and printing admission tickets) and remit the balance of Rs 210.00 to MTA. There will be a reduced fee of Rs.125.00 for each KV and Rs.100 for each JNV student. For such students, the registration centre will remit the entire amount (Rs.125 or Rs.100) to MTA.
  2. All KV and JNV students have to register through their schools to avail the reduced fee.
  3. The PRMO exam portal will be open fromJune 1 to June 30 for centre registration. The centre registration closes on June 30, 2019.
  4. The PRMO exam portal will be open fromJune 1 to July 7 for student registration through registered Centres. Registered centres should start registering students from June 1 to avoid last minute rush.
  5. Non KV and Non JNV students can also directly register for the PRMO exam through the portal. Such registration will be provisional and subject to verification by a designated registration Centre. The link for direct student registration will be available from July 1 to July 7, 2019.
  6. All Kendriya Vidyalaya, Jawahar Navodaya Vidyalaya and Atomic Energy Central Schools may also register as registration centres and may accept to register students from other schools.
  7. The list of “registration centres” will be available on the PRMO exam portal from June 15, 2019 and will be continuously updated till June 30, 2019.
  8. Students can approach one of the approved “registration centres” in this list and register through them for the PRMO exam between June 15 and July 7, 2019 for a fee of Rs 230.00 (and reduced fee of Rs.125.00 for KV and JNV students). Optionally, non KV and non JNV students can also register directly from the portal between July 1 and July 7, 2019 (see para 10 above.) However they must complete the verification process through a designated registration centre.
  9. The KVs and JNV schools will be exam centres. Certain other exam centres may be selected by MTA and will be mentioned on the website.
  10. A carbon copy of the answer (OMR) sheet will be given to the student after the exam; students can check their answers as against the answers which will be uploaded on the MTA website.NOTE: The OMR sheet MUST be retained by the individual student till the conclusion of the Mathematical Olympiad Programme for 2019-20. This will be used for verification purposes for all steps of the Mathematical Olympiad.
  11. From each region, the top (up to) 300 students from Classes 8, 9, 10, 11 and the top (up to) 60 students from Class 12 will be eligible to write the Regional Mathematics Olympiad exam. For the KV, JNV schools which have a countrywide coverage, the number to be selected is up to 5 per cent from Classes 8, 9, 10, 11 and up to 1 per cent from Class 12, of the number of registrations.
  12. Students studying in non-KV and non-JNV schools affiliated to CBSE will belong to their respective geographical regions.
  13. In case of all regions other than KV and JNV, the region to which a student belongs will be determined by the postal address of the school in which a student is studying. Any false information provided at the time of registration in this regard will be treated extremely seriously and will lead to immediate disqualification of the student from all subsequent participation in the Indian Mathematical Olympiad.
  14. The list of students who qualify for RMO will also be announced on the HBCSE website.
  15. All further steps of the Indian Mathematical Olympiad programme, subsequent to the PRMO exam, will be conducted by HBCSE. For details go to this link:


Dr.  S.  Muralidharan

18, Phase 4, Wood Creek County

Near Chennai Trade Center

St. Thomas Mount P.O., Chennai – 600016

Email :



JEE Main 2019 cut off for JEE Advanced 2019 released, more than 2.5 lakh candidates qualify for examination


JEE Main 2019 result was released late Week on Candidates who wish to appear for the JEE Advanced examination are required to appear for and score a minimum marks in JEE Main to qualify for JEE Advanced 2019. NTA has also released the JEE Main cut off for the IIT JEE examination. As many as 24 candidates have scored a perfect 100 percentile to top JEE Main 2019 examinations (April and January combined).

Candidates may please note that unlike previous years, this year the cut off would be based on the NTA score which is a percentile measure of the students’ performance. JEE Main 2019 cut off for JEE Advanced is tabulated below. Please note, the status of candidates to qualify from the various category would be available on their JEE Main 2019

JEE Main 2019 Cut-off of Total NTA Score Based on Paper-I for JEE Advanced 2019
Common Rank List (CRL) Economical Weaker Section (EWS) Other Backward Class (OBC-NCL) Scheduled Caste (SC) Scheduled Tribe (ST) People with Disability (PwD)


78.2174869 74.3166557 54.0128155 44.3345172


The exact number of candidates who have qualified for JEE Advanced 2019 has not been shared by NTA at present. However, a rough estimate suggests that more than 2.5 lakh candidates have qualified for the JEE Advanced which is the entrance test for Indian Institutes of Technology or IIT.

All the candidates who have qualified for JEE Advanced are now required to fill the online application forms on the official website Please note, the online application forms for JEE Advanced would open from May 3, 2019 and close on May 8, 2019. Candidates are required to apply online and pay the fees.

JEE Advanced 2019 examination date was postponed. Due to general elections 2019, JEE Advanced would now be conducted on May 27, 2019. The paper would be completely Computer Based Test. Results for JEE Advanced 2019 would be released in June.



JEE Main Result 2019: Results expected soon on – know how JEE Main Rank would be calculated


JEE Main Result update: There is no confirmation from NTA regarding the declaration date of JEE Main 2019 Result. In January, NTA had released the results on 19th after concluding the examinations on 12th. It is expected that NTA may be able to release the JEE Main 2019 April examination scores today on Experts believe that the rank calculation, however, may delay the results by a day or two. Any update on the result, once available, would be provided on this page.

JEE Main: National Testing Agency, NTA is expected to release the JEE Main Result 2019 soon. The agency would be releasing the result for JEE Main 2019 April examination as well as the JEE Main 2019 Rank and final result. The rank and final result would be considered for qualifying the students for JEE Advanced and for merit lists. Results would be released on Check how JEE Main 2019 rank would

Candidates to please note that the official date for the release of the results have not been shared by NTA. The result is scheduled to be released on or before April 30, 2019. Going by past trends, however, NTA is likely to release the results within this week. Hence, students may keep a check on the official website for any announcement thereof. Updates would also be provided on this page.

As to calculation of the JEE Main 2019 Rank, here are Few things students ought to understand

  • For candidates who have appeared for both January and April examinations of JEE Main, NTA would pick up the better of the two NTA scores. This would be the overall NTA Scores. In case the NTA scores are similar, NTA would then follow the same principal as would be used for deciding a tie for JEE Main Rank. This is to provide the benefit to the student for the same. For students who have appeared only for one examination (either January or April), their NTA scores would be considered.
  • Based on the NTA score, the JEE Main 2019 Rank would be calculated and category wise list released. In case the NTA scores of the candidates tie, then higher rank would be given to
    1. Candidates who have higher NTA score in Mathematics
    2. Candidates who have higher NTA score in Physics
    3. Candidate who is older
    4. In case the candidates tally even after the above three, then the same rank would be awarded to the candidates.

Along with the result and rank, NTA would also release whether or not the candidate has qualified for JEE Advanced 2019. The cut off would also be shared by the agency. Remember, the number 2, 45,000 is not absolute. More number of students (based on the cut off and rank) may be selected for the examination which is now scheduled for May 23, 2019.



NIRF 2019: IIT Madras Again Best Engineering College In India; Check Top 10 List Here


Indian Institute of Technology (IIT) Madras has topped the NIRF ranking for engineering institutes again this year. The names of top 10 engineering colleges in the country was announced by President Ramnath Kovind. This year too the NIRF 2019 rankings for engineering institutes is dominated by IITs with top 8 spots going to IITs. Only two non-IITs ahve made it to the top ten list of engineering colleges in India.

NIRF rankings are a recognition of engineering colleges that fare better in areas such as teaching method, infrastructure, outreach, inclusivity, graduation outcomes and research.

NIRF 2019: Top 10 Engineering Colleges in India

As per the latest NIRF rankings, the top 10 engineering colleges in India are:

  1. Indian Institute of Technology (IIT), Madras
  2. Indian Institute of Technology (IIT), Delhi
  3. Indian Institute of Technology (IIT), Bombay
  4. Indian Institute of Technology (IIT), Kharagpur
  5. Indian Institute of Technology (IIT), Kanpur
  6. ndian Institute of Technology (IIT), Roorkee
  7. Indian Institute of Technology (IIT), Guwahati
  8. Indian Institute of Technology (IIT), Hyderabad
  9. Anna University, Chennai
  10. National Institute of Technology, Thiruchirappalli

For More Detail Visit:-


JEE-2019: Common mistakes JEE aspirants should avoid at any cost


The Joint Entrance Examination (JEE) is the most difficult engineering entrance exam for admission to top institutes in India. JEE consists of Main and Advanced papers.

JEE Main is being held twice in 2019 (January and April). It is a difficult exam and aspirants must ensure there are no flaws in their preparation strategy.Here are some JEE mistakes to avoid at any cost

Don’t start preparation late, have a proper study plan

One of the biggest mistakes JEE aspirants make is starting their preparation late. They must start preparing early so that they have enough time and a systematic approach to cover the entire syllabus. They must know the latest syllabus, exam pattern, weightage, etc. One must plan their study properly and adhere to their schedule. They should focus more on important ones as per weightage.

Do not ignore NCERT books and basic concepts

Some JEE aspirants tend to study only from study material and advanced reference books and ignore basic concepts. However, one must avoid doing this as basics are important. Instead of consulting too many books, they should collect some useful books to avoid confusion. They should first be thorough with NCERT books and then move on to advanced reference books.

Not solving previous papers or not taking mock tests

Another mistake aspirants must avoid is not solving previous question papers and sample papers. They should solve question papers in a timed manner to familiarise with the exam pattern, difficulty level, questioning trends, etc. and manage time better.

They should take mock tests (especially NTA mocks) and analyse their performance on a regular basis, identify weak areas, and work on improving their performance.

Here are some mistakes to avoid during the exam

One of the biggest mistakes students during the exam is not reading the given questions properly. Students tend to misread questions in a hurry or copy incorrect data and end up giving wrong answers. They might also make mistakes in calculations or get confused. This should be avoided too. They should answer only those questions they are confident about to avoid negative marking.

Avoid getting stuck on difficult questions in exam

During the exam, students must also utilise time wisely. They may also find some questions difficult; in such situations, they should avoid getting stuck on those questions as it would be a waste of their time. Instead, they should move on to the remaining questions.


JEE Main 2019 Admit Cards: How to download?


JEE Main 2019 Admit Card: JEE Main April 2019 Admit Card can be downloaded from the official website. National Testing Agency (NTA) will be conducting JEE Main from April 7 to April 12, 2019. The exam will be conducted in computer-based mode except for Drawing Test in Paper 2. The exam for Paper 2 will be conducted only on April 7.

Paper 1 will be conducted from April 8 to April 12.

Candidates will be able to see their exact date and shift from their respective JEE Main 2019 admit cards.

JEE Main 2019 Admit Cards: How to download? 

Step one: Go to official JEE Main 2019 website:

Step two: Click on the admit card link on the home page.

Step three: Login using credentials created at the time of registration.

Step four: Download your JEE Main 2019 Admit Card.

After downloading the admit card, candidates must cross-check the details mentioned on the admit card.

Apart from their JEE Main 2019 admit card, students are not allowed to carry anything else to the exam centre on the allotted exam date. Students who have opted for Paper 2 can bring Geometry Box along with their admit cards on the day of the exam.

The JEE Main April 2019 result for paper 1 will be released by April 30, and the result for Paper 2 will be released by May 15, 2019.


NCERT announces enhancement of the number of scholarships from 1000 to 2000 in NTSE.


Students who wish to appear in the National Talent Search Examination (NTSE) get good news. The number of students receiving the scholarship has got doubled.

  • In the year 2019 the number of scholarship is getting raised from 1000 to 2000.
  • Human Resource Development has decided that the number of students to be selected in the final stage will be increased from one thousand (1,000) to two thousand (2,000).
  • As a result, the number of students selected in the final examination from every state will be doubled.

Selected students will be awarded with scholarship of Rs.1250/- per month of class-XI to XII while Scholarship of Rs.2000/- per month is given Undergraduates and Post-graduates. Amount of Scholarship for Ph.D. is fixed in accordance with the UGC

The examination is conducted in two stages

There are two stages in the selection process. For NTSE Stage-I, Selection is done by States/UTs through a written examination. Students, who Qualify Stage- I, are eligible to appear for NTSE Stage-II examination. Every year about 1.5 lac students appear for the exam in Rajasthan. Out of which 257 students are selected according to the State Quota. These candidates are selected for the final exam. Now state quota has got doubled to 485. Approximately 1.5 Lac students from Rajasthan will be benefitted from this because if the state quota is doubled then almost twice the number of students will be able to appear in the final exam. In this case, the number of students receiving the scholarship also increases.



BITSAT 2019: Application Form, Eligibility, Exam Date, Syllabus


Birla Institute of Technology & Science Admission Test (BITSAT 2019) is held to shortlist candidates for B.E., B. Pharma, M. Sc and various other courses offered by Pilani campus, Hyderabad campus of BITS and K.K. Birla Goa campus. Here is a look at the BITSAT 2019 examination date, eligibility criteria, syllabus and application formalities:

BITSAT 2019 Examination Date


BITSAT 2019 Application Form

Here are the details for BITSAT 2019 application form and application fee:

  • BITSAT 2019 application form shall be available in online mode.
  • The scanned copies of the candidate’s passport size photograph and signature needs to be uploaded with the filled in application form. This shall be uploaded in JPG/ JPEG format.
  • Candidates require filling three preferences for examination centres.
  • The male candidates require submitting an application fee of Rs. 2,950 and the female candidates require submitting an application fee of Rs. 2,450/- along with the application form.
  • For the Dubai examination centre, the candidates require paying Rs. 4,500 as the application fee.
  • Application fee can be paid via Debit card, Credit card and Net banking. It can also be paid by cash via generated Pay-in Slip.

BITSAT 2019 Eligibility Criteria

Here is the eligibility criteria for different courses offered via BITSAT:

  • Candidates must have cleared Class 12thexam from a recognized board in the year 2018.
  • Those appearing in Class 12thexams in 2019 can also apply.
  • Candidates must have Physics, Chemistry and Mathematics as subjects in Class 12th with proficiency in English language. Physics, Chemistry and Biology as subjects are preferred for B. Pharma course though even PCM candidates are eligible for it.
  • Candidates must obtain 75% marks in PCM/ PCB. The minimum score in each subject must be 60%.

Click Here For Download Brochure :- BITSAT2019brochure